GGG: Where would we find the 13th stone? The idealized 13th stone triangle.

In WD Gann's Gravestone Geometry (GGG) where would we expect (lots of assumptions involved) to find it relative to the other 12?

Here's my first drawing using stone 5 (the "gate of Understanding" as I've speculated) and stone 11.  Stones 5 and 11 are two points of the "diamond" of the GGG as demonstrated in a previous essay.  

A vector drawn from stone 5 through stone 11 intersects a vector drawn from stone 7 through the centers of stones 10 and 12 will intersect at point 13.  Point 13 is a first very approximate position where I would expect to find stone 13…if it exists.  Then a vector drawn from stone 1 to point 13.  Here is the very rough first approximation of the very outer triangle of 1-7-13.

So what are the side lengths of the first approximation of triangle 1-7-13?  Based on Google Earth and measuring from centers of the dies of stones 1 and 7 (and we'd expect stone 13) they are:

The first drawing gives us sides of 626, 680 and 648 inches or an average side length of 651.  What self respecting Mason or group of 13 Masons would give us an approximate isosceles triangle?  Was the intention an isosceles triangle and what would be its intended dimensions?  I'd suggest we look to the one entirely known side which is side 1-7.

What is the length of side 1-7?  Presently it is measured at 684 inches based on the centers of the die of each stone.  Since the stones are differing dimensions, might this involve subjectivity?  What is the extreme edge of the two stones; the left edge of stone 1 and right edge of stone 7 as pictured above?  It is darn close to 684 inches depending on how you affix the GPS pin.  I gravitated to 684 because divided by 12 inches per foot you have 57 feet and divided by 3 you have 19 yards.  57 and 19 are both familiar numbers in Mr. Gann's cosmology.  [Recognizing the limitations of measurements of the WD Gann Memorial Triangle, the angles of that triangle were approximately 34, 56, 90.  Perhaps, with better measurements that 56 degree angle would be 57.]

So, piling another assumption on assumptions, heretofore, let's assume the isosceles has a side length of 684 with the next intention of creating the right side originating at the extreme right corner of stone 7 and bisecting the diagonally aligned stones 10 and 12 to arrive 684 inches in that direction at hypothetical point 13.

It then becomes merely a matter of finding the point which satisfies 684 inches from the extreme left of stone 1 and point 13.  Here is the perfect isosceles triangle with side lengths of 684 inches/57 feet/ 19 yards given those assumptions:

I have eliminated the busy internal vectors and I have revealed the yellow GPS "pins" that reveal the exact location of the stones.  Notice how the GGG sits neatly between the rows of the Cemetery's officially laid out rows….something of a "Valley" as described on pg 37 of "The Tunnel Thru the Air."    Notice how estimated point 13 is near the center of the "Great Tree."

The GPS pins at  at stones 1 and 7 should be on the extreme left and right edges, respectively.  The GPS pin at stone 13 should be the center of that stone.  It should be:

From my previous trips I know there to be a stone within a few feet (maybe 3 to 6 feet) from the trunk of the "Great Tree."  I believe that stone to have a medallion on it and I know I have seen a medallion with "Endowed" with the 4-digit endowment reference on it.

On Sunday, August 30, 2015 I'll make another trip with the principle purpose to verify that stone, one way or the other.  This time, in contrast to the previous two trips, I intend on having a more accurate version of the iPhone compass that will take me to the hundredth of a second of GPS.  The onboard compass specifies only the second, so I will have to find a better app to address this.

I will first go to stone 5 which i have otherwise identified as the "GGG Gateway," the correct entrance to the "Vally," and then follow the path laid out on page 37 of TTTTA.  I expect to better identify that path or route according to page 37 in a later post.

I'm just not smart enough to visualize and cut to the chase of this perceived exercise.  I've gotta take it one step at time, make the errors, back up and start again.  Maybe the 3rd time will be the charm.  Prove all things to yourself and cling to that which is good.

Jim Ross